1) Gauri went to the stationers and bought things worth&,. 25, out of which30 paise went on sales tax on taxable purchases. If the tax rate, was 6%, then what was the cost of the tax fie item.
1) 15 rs 2) 15.70 rs
3) 19.70 rs 4) 20 rs Soln.
Solution : Let the amount taxable purchases be X rs.
then 6% of X= 30 paise x x 6=30
Hence, cost of tax fie items
= [25-(5 + 0.30)] rs = 19.70 rs
2) clock X loses one minute a day and clock Y gains 3 minutes per day. If clock Y is 15 minutes ahead of clock X. How many days will it take clock Y to be 35 minutes ahead of clock X
1) 2 2) 3 3) 4 4)5
Solution : Y must be ahead of X by 35-1 5 = 20 minutes
Y gains over clock X = (3 + 1) = 4 minutes
Therefore, required days = 2014 = 5 days.
3) A number is multiplied by 5 and 25 is added to it. The result is divided by 5 and the original number is subtracted fiom the same. The remainder will be v.
1) 5 2) 1 3) 2 4) 3
Solution : Let number is X Multiply by 5, then 5X, added 25 then 5X + 25
Result divided by 5 then = x + 5
Subtracted initial number then x +5 - x = 5 4) The ratio of two numbers is 15: 11. If their HCF is 13, then the numbers are
1) 75,55 2) 45,22
3) 104,44 4) 195,143
Solution :
Let number are 15x and 11x . HCF is 13
Thus only possible numbers are 13 x 15 and 13 x 11
5) In an examination, a student average marks were 63 per paper. If he had obtained 20 more marks for his Biochemistry paper and 2 more mark for his Microbiologj paper, his average per paper would have been 65. How many papers were there in the examination is?
1)11 2)12 3)13 4)14
Solution: Assume there be x papers.
Total marks of all papers = 62x
fiom question, 65x-63x=20+2
2x=22. x=11
6) The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 yrs older. If the ages of these two are excluded, the average ages of remaining player is one year less than the average age of the whole team. What is the average age of the team?
1) 23 VS 2) 24 YrS
3) 25 YrS 4) none of these
Solution: Let the average age of whole team = x yrs
then total age = 11x yrs.
Now, after excluding 2 player the average age = (x-1) hence,
total age = 9(x-1) yrs
Now, 11x-(26+29)=9(x-1)
11x-55=9x-9
2x=46=23
7) 8 men can do a work in 12 days while 20 women can do it in 10 days. In how many days can 12 men and 15 women complete the same work? (days)
1) 5 2) 4 3) 6 4) 7
Solution : Total work to be done = 8x 12 = 96 man-days or total work to be done = 20x 10 = 200 woman-days.
Since the work is the same we can eq uate 96 man-days = 200 woman-days.
Hence 1 man-day= 2.08333 woman-days.
Now if 12 men and 15 women are working on the work we get 12 men are equal to 12 X 2.08333 = 25 women
Hence the work done per day is equivalent to 25 + 15 women working per day.
That is 40 women working per day.
Hence 40xno. ofdays = 200 women days
so number of days = 5 days.
8) There are 200 questions on a 3 hr examination. Among these questions are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems.
1)72 min 2)80 min
3)45 min 4)48 min
Solution : Time taken of 1 math problem = 2 general problems
M = 2G
50M + 150G = 180min
50M + 150/2M = 180min
125M = 180 M = 180/125
Total time taken for 50M problems = 180/125 × 50 = 72 min.
9) The length and breadth of a rectangular plot are in the ratio of 7:5. If the length is reduced by 5 m & breadth is increased by 2 m then the area is reduced by 65 square meters. The length and breadth of the rectangular plot are? (Cms)
1) 25 2) 50 3) 100 4) 22
Solution :
Length, Width= 7x, 5x
(7x – 5) (5x + 2) = (7x × 5x) – 65
x = 5, Length = 35, Width = 25
10) A shopkeeper gives 4 items free of cost with every 21 items and a discount of 25% is also offered on MRP and the shopkeeper still gains 55% profit. Now what is the ratio of CP to MRP?
1)63:124 2)63:125
3)73:125 4)None of these
Solution : 25CP + 55/100 (25 CP) = 21 MRP – 25/100 (21 MRP)
155CP = 63 MRP
CP: MRP = 63: 155
11) A and B invest Rs. 3000 and 4000 respectively in a business. A recei ves Rs. 10 per month out of the pro fit as a remuneration for running the business and the rest of the profit is divided in proportion to the investment. If in a year A totally rec eives Rs. 390, what does B receives ?
1)300 2)400 3)360 4)340
Solution :
A : B = 3000 : 4000
= 3 : 4
A = 390 – 120 = 270 (profit)
3 parts = 270
B receives 4 parts = 360
12) A and B started a business by investing 250 and 3000 respectively. At the end of every month A invested 250 more and B withdraw 250 from his investment. Find in what ratio the profit should be distributed at the end of the year.
1)1:2 2)1:3 3)2:3 4)1:1
Solution : A B
250 3000
250 + 11 (250) 3000 – 11 (250)
3000 250 Profit = 1 : 1
13) Ex:-1. If boat and water are traveling in the same direction, then the boat is said to be in downstream. (Along with)
1)11 2)13 3)12 4)10
Solution :
Boat speed in still water (2x) = 6 kmph
Water speed (v) = 4 kmph
Boat speed in down steam (DS) = u + v
= 6 + 4 = 10 kmph
14) The average age of A,B and C is 26 years, if the average age of A and C is 29 years, what is the age of B in years?
1)12 2)21 3)20
4) None of these
A+B+C = 78
A+C = 58 B = 78 – 58 = 20
15. The fare of a bus is Rs x for the first five kilometers and Rs13 per kilometer thereafter, If a passanger pays Rs 2402 /- for a journey if 187 kilometers, What is the value of x?
1) Rs 29/- 2) Rs 39/-
3) Rs 36/- 4) Rs 31/-
solutuion: [x for first 5 Km + 13x remaining Kms]= Total pay
xRs + 13x182 = Rs 2402
x Rs+ 13 x 182 = Rs 2402
x + 2366 =2402
x = 36 Rs
16. Akash scored 73 marks in subjects A. He scored 56% marks in subject B and x marks in subject C . maximum marks in each subject were 150. the overall percentage marks obtained by Akash in all three subjects together were 54 %. How many marks did he score in subject C
1) 84 2) 86 3) 79 4) 73
Marks is subject B= 56% of 150 =84
total marks obtained = 54% of total marks
17. How many natural numbers are there lying between 134 and 467 which are divisible by 7?
1) 46 2) 47 3) 49 4) 51
Smallest number divisible by 7= 140
Largest number = 462
an = a+(n-1)d
462= 140 + (n-1)7
(n-1)7= 462-140=322
n-1=322/7 = 46
n=46+1=47
Answers
1.3 2.4 3.1 4.4 5.1
6.1 7.1 8.1 9.1 10.2
11.3 12.1 13.4 14.3 15.3
16.2 17. 2
Authorization